Thread: Absolute minimum and maximum of a function involving e
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Old December 4th, 2008, 10:08 AM
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In the case F(x) = e^{-x} - e^{-2x}
the derivative is F'(x) = -e^{-x} +2 e^{-2x}

F'(x) = 0 leads to -e^{-x} +2 e^{-2x} = 0

2 e^{-2x} = e^{-x}

2 = e^x

x = ln(2) which is an absolute max

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