Thread: Integrate Sqrt[x^2-a]?
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Old December 4th, 2008, 02:57 PM
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Quote:
Originally Posted by coverband View Post
mathstud what if a is negative - then we can't consider sqrt(a) ?
Ok then make it \sqrt{x^2+(-a)} and make the sub x=\sqrt{-a}\tan(\theta) or x=\sqrt{-a}\sinh(\theta)
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