View Single Post
  #4  
Old December 27th, 2008, 05:39 AM
Opalg's Avatar
Opalg Opalg is offline
MHF Contributor

 
Join Date: Aug 2007
Location: Leeds, UK
Posts: 2,455
Country:
Thanks: 150
Thanked 1,495 Times in 1,250 Posts
Opalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant futureOpalg has a brilliant future
Default

Quote:
Originally Posted by chiph588@ View Post
I have a couple question regarding the Riemann zeta function and its extension onto the complex plane. I know the function is given by the reflection formula \zeta(s) = 2^s\pi^{s-1}\sin\left(\frac{\pi s}{2}\right)\Gamma(1-s)\zeta(1-s).

My first question is how is this proved?

My second question is how does this extend \zeta(s) to the complex plane?
The zeta function is initially defined as \zeta(s) = \sum_{n=1}^\infty n^{-s}. This series converges for all complex numbers s whose real part is greater than 1. To extend the domain of definition, the usual procedure (as far as I understand it—I'm not an expert in this area) is to use analytic continuation to define it for all s with real part greater than 0 (except for the pole at s=1). An intricate argument using contour integration (as in the previous comments) then establishes the functional equation for s in the strip 0<re(s)<1. The functional equation is then used to define \zeta(s) in the remainder of the complex plane.
Reply With Quote
The following users thank Opalg for this useful post:
Donate to MHF