Thread: gamma and e^(-x^2)
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Old December 31st, 2008, 09:00 PM
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Since we're on Gamma, derive this one:

{\Gamma}(2n)=\frac{1}{\sqrt{\pi}}\cdot 2^{2n-1}\cdot {\Gamma}(n)\cdot {\Gamma}(n+\frac{1}{2})

This is the duplication formula for Gamma.

Try using the identity 2sin{\theta}cos{\theta}=sin2{\theta} and put 2{\theta}={\phi}


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