Thread: Describing the function
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Old December 31st, 2008, 10:04 PM
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so for a) \lim_{x \to 0}f(x) f(x)=-\infty ?

a)the zeros are x=1 and x=-1 this is because \frac{x^3-x}{x^3-4x}=\frac{x(x^2-1)}{x(x^2-4)}=\frac{x^2-1}{x^2-4} so x^2-1=0, x=+/- 1, correct?

b and c were easy, but d is still a little confusing, so far from what i have, it is an even function, correct?

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Last edited by OnMyWayToBeAMathProffesor; December 31st, 2008 at 10:15 PM.
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