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Old January 1st, 2009, 12:06 AM
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Originally Posted by OnMyWayToBeAMathProffesor View Post
so for a) \lim_{x \to 0}f(x) f(x)=-\infty ? Mr F says: This is not correct. Go back to what Jhevon said in post #3 about the common factor.

a)the zeros are x=1 and x=-1 this is because \frac{x^3-x}{x^3-4x}=\frac{x(x^2-1)}{x(x^2-4)}=\frac{x^2-1}{x^2-4} so x^2-1=0, x=+/- 1, correct?

b and c were easy, but d is still a little confusing, so far from what i have, it is an even function, correct?

Happy New Year!
Post #4 contains the ideas needed to answer d).
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