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Quote:

Originally Posted by asi123

Thanks a lot guys.
I have a question due, is this substitute $z = e^{it}$ usually works?

Integration around the contour $|z| = 1$ , that is, making the substitution $z = e^{it}$ , is typically used to evaluate a real integral of the form $\int_0^{2 \pi} F(\cos t, \sin t) \, dt$ .

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