Thread: probability
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Old January 1st, 2009, 07:54 AM
Constatine11 Constatine11 is offline
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Let p_d be the probability of a draw, p_b probability of B winning and p_a the probability of A winning.

Then:

3 p_d=p_b

2 p_b=p_a=6 p_d

and of course:

p_a+p_b+p_d=1

or:

6 p_d+3p_d+p_p=1

so:

p_d=1/10

as Mr Fantastic has.

Now the ony way out I can see is if the question asked for the odds of a draw since the odds are the ratio of favourable to unfavourable outcomes the odds are 1:9.

.
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