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Old January 2nd, 2009, 11:42 AM
frog09 frog09 is offline
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Default Integration of Logaritmic Functions

\int_1^3 (x+3)/(x^2+6x) dx = ?

I tired separating and simplifying the problem into two different integrals:

\int_1^3 1/(x+6) +\int_1^3 3/(x^2+6x)

and get...
\int_1^3 ln(x+6) + \int_1^3 3ln(x^2+6x)

evaluating I get

[ln9-ln7]+ 3[ln27+ln7]

but that is not any of the solutions.
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