Thread: Statistics, averages and deviations.
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Old January 4th, 2009, 02:00 PM
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Originally Posted by RossBrons View Post
And is the standard deviation of \bar{X} = \frac{\sigma}{\sqrt{n}} Mr F says: Yes.

Mr Fantastic, I can't understand how to apply the math on that wiki article. Kind Regards,
Ross
\mu_{\overline{X}} = \mu.

\sigma_{\overline{X}} = \frac{\sigma}{\sqrt{n}}.

Substitute \mu = 6.0 and \sigma = 3.29 and n = 2.

It's that simple.
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