View Single Post
  #3  
Old January 6th, 2009, 09:22 AM
earboth's Avatar
earboth earboth is offline
Super Member

 
Join Date: Jan 2006
Location: Germany
Posts: 4,182
Country:
Thanks: 177
Thanked 1,805 Times in 1,657 Posts
earboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant futureearboth has a brilliant future
Default

Quote:
Originally Posted by magentarita View Post
From a point 100 feet away in front of a public library, the angles of elevation to the base of the flagpole and the top of the flagpole are 28 degrees and 39 degress 45', respectively. The flagpole is mounted on the front of the building's roof. Find height of the flagpole.

Must I change 39 degrees 45' into a degree first?

How is this done?
1. 45' = \left(\dfrac{45}{60}\right)^\circ = 0.75^\circ

2. You are dealing with 2 right triangles. Use tan-function to calculate the second leg:

The length of the flagpole is:

f = 100\cdot \tan(39.75^\circ) - 100\cdot \tan(28^\circ) = 100 \cdot (\tan(39.75^\circ) - \tan(28^\circ)) = 29.998...\approx 30'
Attached Thumbnails
height-flagpole-flagpole.png  
Reply With Quote
The Following 2 Users Say Thank You to earboth For This Useful Post:
Donate to MHF