Thread: Need help verifying this(trig related):
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Old January 6th, 2009, 03:53 PM
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\cos\left(\frac{\pi}{6} + \frac{\pi}{3}\right) = \cos\left(\frac{\pi}{2}\right) = 0

\cos\left(\frac{\pi}{6}\right)\cos\left(\frac{\pi}{3}\right) - \sin\left(\frac{\pi}{6}\right)\sin\left(\frac{\pi}{3}\right)

look at your unit circle and evaluate the above expression ... you should get 0, right?
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