Thread: Need help verifying this(trig related):
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Old January 6th, 2009, 03:58 PM
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a = \frac{\pi}{6} and b= \frac{\pi}{3}

\cos( \frac{\pi}{2}) = 0

\cos( \frac{\pi}{6}).\cos( \frac{\pi}{3})-\sin( \frac{\pi}{6}).\sin( \frac{\pi}{3}) \rightarrow \frac{\sqrt{3}}{4}-\frac{\sqrt{3}}{4}

This what you mean?
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