Thread: Continuous Random Variable with Distribution!
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Old January 6th, 2009, 04:43 PM
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Quote:
Originally Posted by Pringles View Post
P(x)={k(1-x^3) 0< or = x < or = 1
0 otherwise

Evaluate k
For this to be a pdf, \int_{-\infty}^{\infty}P\left(x\right)\,dx=1

Thus, solve the equation \int_{-\infty}^{\infty} k\left(1-x^3\right)\,dx=1\implies \int_0^1 k\left(1-x^3\right)\,dx=1 for k.

Can you take it from here?
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