Thread: prove i^2 =-1
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Old January 7th, 2009, 07:50 PM
dixie dixie is offline
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Default prove i^2 =-1
prove i^2 =-1 and hence that (u+iv)(x+iy) = (ux-yv) + i(xv +uy)
hint prove that if i^2 =A+iB, then A=-1 and B=0.

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