Quote:
Originally Posted by Bradley55 so we know the expected value is -12.27
i got 3.86 for how much the game should cost for the game to be fair.
right?
i did (10/22)(x-1)+(5/22)(x-2)... so on and plugged that equation into y1. and x into y2, the intersected at 3.86,3.86 |
No.
For the game to be fair you require the expected value of the money you win to be zero.
Let the cost per game be C. Then you require 0 = 7.73 - C.