Thread: integration question
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Old January 12th, 2009, 07:44 AM
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Quote:
Originally Posted by coyoteflare View Post
y=\frac{4}{x^2}

why is this

y=\frac{4x}{x^3}

and not

y=\frac{4x}{0.3333x^3}


sorry i dont know hwo to do a fraction in a fraction so 0.33333 = one third
Are you trying to integrate \frac{4}{x^2} i.e.

\int \frac{4}{x^2}\, dx?
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