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Old January 12th, 2009, 08:53 AM
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Quote:
Originally Posted by coyoteflare View Post
heres the question

A is the point (2,1) on the curve y=\frac{4}{x^2}

use calculas to find the gradient of the curve at A
Oh, you want the slope of the tangent. In this case you'll need the derivative. So

\frac{d}{dx} \left( \frac{4}{x^2} \right) = \frac{d}{dx} \left( 4 x^{-2} \right)

Once you have this, evaluate it at x = 2 and you'll have your answer.
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