Thread: trig substitution and integration by parts
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Old January 14th, 2009, 09:00 PM
Jameson Jameson is offline
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This isn't a circle. But yes you can use trig substitution. You have y= \pm \sqrt{3^2-(2x)^2} Let the hypotenuse of a right triangle be 3, the vertical leg be 2x, and the other leg be 9-4x^2.

edit: well i am very far behind
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