March 13th, 2009, 06:32 PM
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 | Flow Master | | Join Date: Dec 2007 Location: Zeitgeist
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Quote:
Originally Posted by smmmc  hi
q1- The system of equations y = x^2 − 4x + c and y = −7x + 8 has two solutions, one at
x = 1, and another at x = −4. Find the value of c.
i made the 2 equations equal to each other so
x^2 − 4x + c= −7x + 8
so rearrange
x^2 + 3x -8 +c
sub x=-1 in
so it would be c=4 but then i thought to factorise the equation and use null factor law to find c? Mr F says: Why would you do that? Substitute x = 1 => c = 4. Substitute x = -4 => c = 4. Solved.
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