Thread: LCD, first grade equation, solving help
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Old April 19th, 2009, 12:49 PM
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Quote:
Originally Posted by strunz View Post
\frac{8}{y-2}-\frac{13}{2}=\frac{3}{2y-4}

LCD must be 2y-4

(\frac{8}{y-2})(\frac{2y-4}{2y-4})-(\frac{13}{2})(\frac{2y-4}{2y-4})=(\frac{3}{2y-4})(\frac{2y-4}{2y-4})

then

(16y-32)-(26y-52)=6y-12
16y-32-26y+52=6y-12
-16y=-32
y=2

Someplace I've must made a mistake as my book says y=3. Somebody?
Thanks
\frac{2 \cdot 8}{2(y-2)}-\frac{13(y-2)}{2(y-2)}=\frac{3}{2y-4}

try again.
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