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Old April 22nd, 2009, 09:57 AM
strunz strunz is offline
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Quote:
Originally Posted by skeeter View Post
\frac{2 \cdot 8}{2(y-2)}-\frac{13(y-2)}{2(y-2)}=\frac{3}{2y-4}

try again.
I don't get it.

16 -13y-26 = 3

y= 1
y is supposed to be 3

Some site I can find that could be of help here?
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