According to that page, s(t) is your distance. And at t = 0, s = 1.

V(t) is a velocity-time graph. When you integrate V over a span of dt, you essentially get v * s (or m/s * s), which is just m.



The integral yeilds s(t) = x^3 + x^2 + c. And again, at t = 0, s = 1.

1 = (0)^3 + (0)^2 + c

Thus c = 1.