View Single Post
  #2  
Old April 30th, 2009, 12:20 PM
derfleurer derfleurer is offline
Member
 
Join Date: Apr 2009
Posts: 166
Country:
Thanks: 2
Thanked 58 Times in 58 Posts
derfleurer will become famous soon enough
Send a message via MSN to derfleurer
Default

x^3 = 2 - x @ x = 1

So from 0 to 1, we have the area under x^3. And from 1 to 2, we have area under 2 - x.

\int_{0}^{1} x^3dx + \int_{1}^{2} (2 - x)dx
Reply With Quote
The following users thank derfleurer for this useful post:
Donate to MHF