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Old April 30th, 2009, 11:22 AM
Tweety Tweety is offline
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Quote:
Originally Posted by derfleurer View Post
x^3 = 2 - x @ x = 1

\int_{0}^{1} x^3dx + \int_{1}^{2} (2 - x)dx
How did you work out x=1?
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