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Old May 21st, 2009, 11:29 AM
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Quote:
Originally Posted by epiekarc View Post
I understand how z and y were drawn in, what i dont understand is how or why we can calculate the angle. I was thinking about this problem some more and thought that if we drew in a circle and used the intersection of z and y as the mid point then i should be able to calculate for the lowest z-axis point value of the circle. I just don't know how to figure that out.
According to my previous post you'll get a rectangle in the X-plane where z' is parallel to the line of intersection between the plane X and the plane Y.

The angle d has the diagonal and the side y' as it's legs. Use the right triangle painted light grey to calculate the angle d:

\tan(d)=\dfrac{z'}{y'}~\implies~ d= \arctan\left(\dfrac{z'}{y'}  \right)
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