May 23rd, 2009, 11:22 PM
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 Complex numbers and triangles?
If  be the complex numbers represented by the vertices  of a triangle  in anticlockwise order, show that: ![\left|\sum \frac{z_2 - z_3}{z_1}|z_1|^2\right|\cos A - 2R[(z_1 - z_2)(\bar{z_1} - \bar{z_2})]\sin A = 0](http://www.mathhelpforum.com/math-help/latex2/img/4af3baf52b58312bce0ba81602f1d310-1.gif "\left|\sum \frac{z_2 - z_3}{z_1}|z_1|^2\right|\cos A - 2R[(z_1 - z_2)(\bar{z_1} - \bar{z_2})]\sin A = 0") |