Thread: Solving a trigonometric equation --> help needed!
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Old June 5th, 2009, 01:56 PM
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Quote:
Originally Posted by s3a View Post
Can someone help me with fully illustrated steps for the following please?:

Solve the following trigonometric equation. Give the exact value(s).

2 sin^2 (x) - 3 cos (x) = 3 x ∈ [0, π]

Any help would be greatly appreciated!
Thanks in advance!
2(1-cos^2(x))-3cos(x)=3

2-2cos^2(x)-3cos(x)-3=0

-2cos^2(x)-3cos(x)-1=0

(-2cosx-1)(cosx+1)=0

so the first is zero or the second find when the first zero and when the second zero
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