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Old June 6th, 2009, 05:06 AM
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Quote:
Originally Posted by db5vry View Post
part a] confuses me in terms of the multiplication. When I have
\frac{1}{X} \frac{6}{5}x^2 - \frac{6}{5}x dx
I canceled it down to \frac{6}{5}x - \frac{6}{5}
And integrated it to \frac{\frac{6}{5}x^2}{2} - \frac{6}{5}x between the limits of 2 and 1
So I ended up with 2\frac{2}{5} - - \frac{3}{5} and got 3 as the value.
It doesn't seem right. Is this really how it is done?
Thanks for helping :]
\frac{6}{5} \left[\frac{x^2}{2} - x \right]_1^2 \neq 3. Check your arithmetic.
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