Thread: Continuous Random Variable question. Could you help?
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Old June 6th, 2009, 06:00 PM
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Originally Posted by db5vry View Post
So you take the \frac{6}{5} out as a constant! If I do that then I get 0 - - \frac{3}{5} and an answer of \frac{3}{5}. Is this correct this time?
I will get there in the end. Thanks for pointing this out
If you take the 6/5 out the arithmetic is simpler. But the answer is no different to if you don't take it out ....

3/5 is the corerct answer.
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