Thread: Translation of axes
View Single Post
  #1  
Old June 22nd, 2009, 07:30 AM
mj.alawami mj.alawami is offline
Member
  
Join Date: Jan 2009
Posts: 164
Country:
Thanks: 105
Thanked 1 Time in 1 Post
mj.alawami is on a distinguished road
Default Translation of axes
For the equation,find it's new equation if the origin is translated to the new origin as indicated.
x^2+y^2-8x-10y+12 ; O(1,1)
Attempt:
x=x'+1 , y=y'+1
(x+1)^2+(y+1)^2-8(x+1)-10(y+1)+12=0
=x^2+y^2-6x-8y-4=0

Am I correct ?
Thank you
Reply With Quote