Thread: Translation of axes
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Old June 23rd, 2009, 01:03 PM
mj.alawami mj.alawami is offline
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Default Translation of axes
Find the new equation of the circle of the equation x^2+y^2-4x+6y+9=0 after the translation that moves the origin to the point (2,-3)

Attempt
x=x-2
y=y+3

(x-2)^2 +(y+3)^2 -4(x-2)+6(y+3)+9=0
x^2+y^2-8x+12y+48=0

Am I correct?
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