Thread: A geometric problem I am having issues with...
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Old June 25th, 2009, 09:32 PM
Shyam Shyam is offline
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Quote:
Originally Posted by M23 View Post
This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... Correct to the nearest tenth, the value of x is A. 5.2 B. 5.3 C. 5.4 D. 5.5
Use Pythagorean theorem in RIGHT TRIANGLE PBC,

PC^2=PB^2+BC^2

PC^2=9^2+5^2

PC=10.3

x = 10.3 - 5 = 5.3

Spoiler:
Pythagorean Theorem in Right Triangle

a^2 = b^2+c^2

\Rightarrow(Hypotenuse)^2 = (first\;side)^2+(second \;side)^2
Last edited by Shyam; June 25th, 2009 at 10:04 PM.
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