Thread: A geometric problem I am having issues with...
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Old June 25th, 2009, 09:38 PM
Shyam Shyam is offline
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Quote:
Originally Posted by M23 View Post
This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... 2. Correct to the nearest half of a degree, the measure of angle ADB is: A. 30.5° B. 32.0° C. 34.5° D. 36.0° Thank you for the help!
IN Right triangle PBC,

\tan P = \frac{5}{9}

P = 29.05^\circ

\angle C = 180 - 90 -29.05 = 60.95^\circ

\angle D = \frac{ 60.95}{2}=30.47=30.5^\circ

Spoiler:
\angle D = \frac{\angle C}{2}
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