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Old June 25th, 2009, 10:35 PM
JoAdams5000 JoAdams5000 is offline
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Default Osculating Circle for a Curve

I lost trying to find the osculating circle for the curve defined by r(t) = <sint, cost, -pi + t> at the point t=pi.

Ive calculated the radius of the circle to be 1 and I know I need to somehow use the unit normal vector at point t=pi, which is <0, 1/sqrt(2), 0> to solve for the osculating circle's centre, but I do not know how to do that.

Thans for your help!
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