June 25th, 2009, 11:35 PM
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 | Grand Panjandrum | | Join Date: Nov 2005 Location: South of England
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Quote:
Originally Posted by JoAdams5000  I lost trying to find the osculating circle for the curve defined by r(t) = <sint, cost, -pi + t> at the point t=pi.
Ive calculated the radius of the circle to be 1 and I know I need to somehow use the unit normal vector at point t=pi, which is <0, 1/sqrt(2), 0> to solve for the osculating circle's centre, but I do not know how to do that.
Thans for your help! | That is not a unit vector.
CB |