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Old June 27th, 2009, 02:02 AM
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Quote:
Originally Posted by tagiraldo View Post
Assume the market proportion of the phone provider XY to be 50% in a given country. Assume it means that 50% of all existing phone numbers in the country are of the provider XY.


b) What is the probability that 2 phone numbers out of 10 randomly selected are of the provider XY?

c) What is the probability that at least 2 phone numbers out of 10 randomly selected are of the provider XY?
The number of XY's in a sample of size N has a binomial distribution B(p_{XY},N). This will give the answer to b) straight off, for part c) you will need to sum the appropriate binomial probabilities.

Quote:
d) If 100 numbers have been randomly selected, what is the probability that the we find at least 48 and less than 52 numbers that are of the provider XY?
For this use the normal approximation to the binomial.

CB
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