Thread: Osculating Circle for a Curve
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Old June 27th, 2009, 01:16 PM
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In addition to my previous post I've attached a drawing containing

the curve: \overrightarrow{r(t)}=(\sin(t), \cos(t), -\pi+t)

the tangent: t: \overrightarrow{r(t)}=(0,-1,0)+t \cdot (-1,0,1)

the circle: \overrightarrow{r(t)}=(\sin(t), \cos(t), -\sin(t))
Attached Thumbnails
osculating-circle-curve-raumkurve_tang_krummkreis.png  
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