Thread: distribution probability
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Old June 30th, 2009, 05:23 PM
WillB WillB is offline
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Yes, they give this equation at the top of the normal distibution table
P(Z \le z)=\int^{z}_{-\infty}\frac{1}{\sqrt{2\pi}}e^{-w^{2}/2}dw I see that W=\frac{X-\mu}{\sigma}, so w should be the same thing.
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