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chromium · #1 June 30th, 2009, 06:57 PM

Grades for 2 classes, X and Y

X:78,89,81,94,60,67,51,73,90,93,81,68,45,100,60,10 2,95,87,85,96,77,79,55,89,86,75,85,76,95,84

I calculated $\bar{x}=79.866667$ , $s^{2}_{x}=216.46$ and n=30

Y:65,95,94,72,56,87,89,28,71,78,54,93,91,68,88,90, 69,78,69,91

$\bar{Y}=76.3$ , $s^{2}_{Y}=293.27$ and m=30

a. test the hypothesis $H_{0}: \mu_{X}-\mu_{Y}$ against the alternative $H_{1}: \mu_{X}>\mu_{Y}$ at the $\alpha =0.10$ significance level assuming X and Y are $N(\mu_{X},\sigma^{2}_{X})$ and $N(\mu_{Y},\sigma^{2}_{Y})$ where $\sigma^{2}_{X}=\sigma^{2}_{Y}$

I started by using $t=\frac{\bar{X}-\bar{Y}}{S_{p}\sqrt{1/n+1/m}}$ and critical region $t \ge t_{0.10}(48)=1.299$

b. test the hypothesis $H_{0}: \sigma^{2}_{X}=\sigma^{2}_{Y}$ against the alternative hypothesis $H_{1}: \sigma^{2}_{X} doesn't = \sigma^{2}_{Y}$ at the $\alpha$ =10% significance level.

I started this part with $F=\frac{s^{2}_{x}}{s^{2}_{Y}}$ and $F \ge F_{0.05,29,19}=2.04$ I don't know how to do this because 29 and 19 are not in the table. If this equality is true though then is H0 rejected?