Thread: Random Variables, Density function
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Old July 2nd, 2009, 01:38 PM
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f(x) = ke^{\text{-}hx} for x \ge 0


so k \int_{0}^{\infty} e^{-hx} \ dx = 1

and after you find k (which is in terms of h)

E(X) = k \int^{\infty}_{0} xe^{-hx} \ dx
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