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Old July 3rd, 2009, 05:16 PM
wellfed wellfed is offline
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Quote:
Originally Posted by Jose27 View Post
Suppose 0 \leq a_1 \leq ...\leq a_n \leq ... and that \lim_{n \rightarrow \infty} na_n=L then \sum_{i=1}^n {a_i}\leq na_n \leq L for all n \in \mathbb{N} and so the series converges.

but then a_n=0 for all n \in \mathbb{N} so it doesn't work. I'll check it later.
your assumption 0 \leq a_1 \leq ...\leq a_n \leq ... and that \lim_{n \rightarrow \infty} na_n=L are not compatible.
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