hi

can some one please check this for me

need to evaluate integral x(7-3x^2) for x=6 to x=4

i did this 1/2(7-3x^2)(2x)dx

1/2 *1/2(7-3x^2)^2+c

1/4(7-3x^2)^2+c

then for x=6 to x=4

1/4(7-3(6)^2-1/4(7-3(4)^2

am i on the right track ?

wayne