Thread: [SOLVED] Trig equation
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Old July 4th, 2009, 08:39 AM
JannetheSwede JannetheSwede is offline
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Quote:
Originally Posted by skeeter View Post
\frac{\cos{x} - \frac{1}{2}}{\cos{x}} = \frac{1}{2}

\frac{2\cos{x} - 1}{\cos{x}} = 1

2\cos{x} - 1 = \cos{x}

\cos{x} = 1

x = 2k\pi , k \in \mathbb{Z}
Yea thats one of three awnsers, but what i'm looking for are the other two... :S

btw, just to clearify cosx-\frac{\frac{1}{2}}{cosx}=\frac{1}{2}
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