Thread: [SOLVED] Trig equation
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Old July 4th, 2009, 08:53 AM
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skeeter skeeter is offline
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Originally Posted by JannetheSwede View Post
ok, i have changed the initial question to clearify what it was
\cos{x} - \frac{\frac{1}{2}}{\cos{x}} = \frac{1}{2}

multiply every term by 2\cos{x} ...

2\cos^2{x} - 1 = \cos{x}

2\cos^2{x} - \cos{x} - 1 = 0

(2\cos{x} + 1)(\cos{x} - 1) = 0

\cos{x} = -\frac{1}{2} ... \cos{x} = 1

you finish up.
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