Thread: [SOLVED] Trig equation
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Old July 4th, 2009, 08:56 AM
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2cos^2x-cosx-1=0

cosx=1,\frac{-1}{2}

Spoiler:

cosx=1 gives x=2n\pi

cosx=\frac{-1}{2} gives x=\frac{2\pi}{3},\frac{4\pi}{3}
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