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Old July 4th, 2009, 09:22 AM
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Hello banana_banana
Quote:
Originally Posted by banana_banana View Post
4. Find the area of the largest isosceles triangle inscribed in a semi-circle of radius 10 ft, the vertex of the triangle being at the center of the circle.
Let the angle between the radii forming the two equal sides of the triangle be \theta. Then the area of the triangle is given by

A = \tfrac12.10^2\sin\theta = 50\sin\theta

\Rightarrow \frac{dA}{d\theta} = 50\cos\theta = 0 when \theta = \tfrac{\pi}{2}

Can you finish it now?

Grandad
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