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Old July 4th, 2009, 08:51 PM
artvandalay11 artvandalay11 is offline
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Quote:
Originally Posted by helloying View Post
Find the coordinates of the points of itersection A and B of the line 2x+y+2=0 and the curve 1/x +2/y= 1/2

i reform the eqn of the line to be y=-2-2x and the curve is \frac{2}{(0.5-1/x)}

then i sub the two eqn and i 2=(0.5-1/x)(-2-2x)

and so x=-2. but i only got one ans and the qn say there are two point of intersection. How to solve this qn?
y=-2-2x, and substitute to get \frac{1}{x}+\frac{2}{-2-2x}=\frac{1}{2}
\frac{1}{x}-\frac{1}{1+x}=\frac{1}{2}

\frac{1+x}{x(1+x)}-\frac{x}{x(1+x)}=\frac{1}{2}

\frac{1}{x+x^2}=\frac{1}{2}

x+x^2=2
x^2+x-2=(x+2)(x-1)=0

x=1 and x=-2 and therefore y=-4 and y=2

so (1,-4) and (-2,2)
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