Thread: Sequence and Series
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Old August 17th, 2009, 06:34 PM
naikn naikn is offline
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Quote:
Originally Posted by Bruno J. View Post
Well \sum_{n=1}^\infty \frac{2}{4^n}=2\sum_{n=1}^\infty \frac{1}{4^n} which is also a geometric series...

so does that mean that in that portion of the problem (1/4^n)

a=1/4 r=1/4 and you would use the formula a/1-r in order to find the sum
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