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Old September 24th, 2009, 11:25 PM
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Originally Posted by spearfish View Post
ok, so if I multiply them the first multiple would be 4*6*7 = 168. However, 84 is a common multiple of 4,6, and 7, so it seems this doesn't do the trick. Or am I missing something?
Since 4 \times 6 \times 7 = 2^2 \times 2 \times 3 \times 7 = 2 \times 2^2 \times 3 \times 7, any common multiples of 2^2 \times 3 \times 7 will be a multiple of 4, 6 and 7.
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